1z1-071 Test Answers - Oracle Database SQL Test Torrent & 1z1-071 Guide Torrent
1z1-071 Test Answers - Oracle Database SQL Test Torrent & 1z1-071 Guide Torrent
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Tags: 1z1-071 Certification Training, 1z1-071 Valid Test Testking, 1z1-071 Reliable Dumps Files, Exam 1z1-071 Simulator Free, 1z1-071 Test Guide
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The Oracle 1z1-071 Exam consists of 73 multiple-choice questions, and you have 105 minutes to complete it. The passing score for the 1z1-071 exam is 63%. 1z1-071 exam can be taken online or in-person at a Pearson VUE testing center. 1z1-071 exam fee is $245, and you can register for the exam on the Oracle website.
The Oracle 1z1-071 exam consists of 73 questions and has a time limit of 100 minutes. The questions are of multiple-choice format and cover a wide range of topics, including SQL concepts, data manipulation, data definition, and SQL queries. Candidates who pass the exam will receive a certification that demonstrates their proficiency in SQL and can help them advance their careers as database developers or administrators.
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Oracle Database SQL Sample Questions (Q171-Q176):
NEW QUESTION # 171
View the Exhibit and examine the structure of the ORDER_ITEMS table.
You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?
- A. SELECT order_id
FROM order_items
WHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity)
FROM order_items
GROUP BY order_id) - B. SELECT order_id
FROM order_items
WHERE(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)
FROM order_items) GROUP BY order_id); - C. SELECT order_id
FROM order_items
WHERE(unit_price*quantity) = MAX(unit_price*quantity)
GROUP BY order_id); - D. SELECT order_id
FROM order_items
GROUP BY order_id
HAVING SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)) FROM order_items GROUP BY order_id);
Answer: D
NEW QUESTION # 172
View the Exhibit and examine the structure of the EMPLOYEES and JOB_HISTORY tables.
Examine this query which must select the employee IDs of all the employees who have held the job SA_MAN at any time during their employment.
SELECT EMPLOYEE_ID
FROM EMPLOYEES
WHERE JOB_ID = 'SA_MAN'
-------------------------------------
SELECT EMPLOYEE_ID
FROM JOB_HISTORY
WHERE JOB_ID = 'SA_MAN';
Choose two correct SET operators which would cause the query to return the desired result.
- A. MINUS
- B. UNION ALL
- C. INTERSECT
- D. UNION
Answer: B,D
NEW QUESTION # 173
Which CREATE TABLEstatement is valid?
- A.
- B.
- C.
- D.
Answer: A
NEW QUESTION # 174
Examine the description of the EMPLOYEES table:
NLS_DATE FORMAT is DD-MON-RR.
Which two queries will execute successfully?
- A. SELECT dept id, MAX (SUM(salary)) FROM employees GROUP BY dept_id;
- B. SELECT dept_ iD, sum(salary) FROM employees WHERE hire_date > '01-JAN-9' GROUP BY dept_id;
- C. SELECT dept_ id, AVG(MAX(salary)) FROM employees GROUP BY dept_id, salary;
- D. SELECT AVG(MAX(salary)) FROM employees GROUP BY salary;
- E. SELECT dept_ id, AVG (MAX(salary)) FROM employees GROUP By dept_id HAVING hire_date> ' O1-JAN-19';
Answer: B,D
NEW QUESTION # 175
See the Exhibit and examine the structure of the PROMOTIONS table:
Using the PROMOTIONS table,
you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:
What would be the outcome?
- A. It generates an error because CASE cannot be used with group functions.
- B. It generates an error because NULL cannot be specified as a return value.
- C. It executes successfully and gives the required result.
- D. It generates an error because multiple conditions cannot be specified for the WHEN clause.
Answer: C
Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END
NEW QUESTION # 176
......
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